• a 1500 kg car skids to a halt on a wet road where μk = 0.50.

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  • The stopping force on the car is equal to the mass of the car multiplied by the acceleration due to friction. Thus, the stopping force on the car is equal to 1500 kg x (μk x g) = 1500 kg x (0.50 x 9.81 m/s2) = 7365.5 N.

    • Answered:

      Nancy Rivers

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