
how much power is the 20ω resistor dissipating?
 Physics

Author:
michellerivera663  1 month ago

Answers: 2

The 20Ω resistor is dissipating 100 watts of power. This can be calculated using Ohm's Law (P = V2/R), where P is the power dissipated, V is the voltage across the resistor and R is the resistance of the resistor. In this case, V is 200 volts, so the power dissipated is 200 x 200 / 20 = 100 watts.

Answered:
Darren Jackson

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The power dissipated by a resistor is given by the formula P = V^2/R, where V is the voltage across the resistor and R is the resistance. In this case, if we assume the voltage across the 20Ω resistor is 1V, then the power dissipated is 0.05 Watts (0.05 W).

Answered:
Madelynn Hull

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