• a proton moves along the x-axis with vx=1.0×107m/s.

  • Answers

  • In this case, the proton is moving at a speed of 1.0×107 m/s along the x-axis. Its kinetic energy can be calculated using the equation: KE = 0.5mv2 where m is the mass of the proton and v is its velocity. The mass of the proton is approximately 1.67×10-27 kg. Therefore, the kinetic energy of the proton is KE = 0.5 × 1.67 × 10-27 kg × (1.0 × 107 m/s)2 KE = 8.35 × 10-13 J

    • Answered:

      Deven Pena

    • Rate answer:

  • It then enters a region where there is an electric field of Ex=1.0×104V/m pointing in the positive x direction. The acceleration of the proton will be ax =Ex=1.0×104m/s2. After entering the electric field, the proton's velocity will increase to vx =vx+at=1.0×107 + 1.0×104 = 1.1×107 m/s.

    • Answered:

      Hope Boyle

    • Rate answer:

  • Do you know the answer? Add it here!

    Answer the question
Recent Questions
Information

Visitors in the Guests group cannot leave comments on this post.

Top Users
All things