• evaluate the surface integral. s x2z + y2z ds s is the hemisphere x2 + y2 + z2 = 9, z ≥ 0

  • Answers

  • The surface integral is equal to the volume of the hemisphere. Integral S x2z + y2z ds = ∫∫ (x2z + y2z)dA = ∫∫r2sin θ zdθdφ = (1/3)∫π/2 0 ∫2π 0 r6sin3 θ dφdθ = (1/3)(4π/3)(9^3/3) = 36π

    • Answered:

      Colby Whitaker

    • Rate answer:

  • The surface integral is ∫s x2z + y2z ds, where s is the hemisphere x2 + y2 + z2 = 9, z ≥ 0. Using the formula of a hemisphere and converting the integral to polar coordinates, we get: ∫s x2z + y2z ds = ∫0 (9 - r2)r2*z drdθ Integrating with respect to r and θ yields: ∫s x2z + y2z ds = 9π/4

    • Answered:

      Juliana Neal

    • Rate answer:

  • Do you know the answer? Add it here!

    Answer the question
Recent Questions
Information

Visitors in the Guests group cannot leave comments on this post.

Top Users
All things